### Bananas, Lenses, Envelopes and Barbed Wire A Translation Guide

One of the papers I've been slowly rereading since summer began is "Functional Programming with Bananas, Lenses, Envelopes and Barbed Wire", by Erik Meijer, Maarten Fokkinga and Ross Paterson. If you want to know what {cata,ana,hylo,para}morphisms are, this is the paper to read: section 2 gives a highly readable formulation of these morphisms for the beloved linked list.

Last time, however, my eyes got a little bit glassy when they started discussing algebraic data types, despite having used and defined them in Haskell; part of me felt inundated in a sea of triangles, circles and squiggles, and by the time they reached the laws for the basic combinators, I might as well have said, "It's all math to me!"

A closer reading revealed that, actually, all of these algebraic operators can be written out in plain Haskell, and for someone who has been working with Haskell for a little bit of time, this can provide a smoother (albeit more verbose) reading. Thus, I present this translation guide.

Type operators. By convention, types are $A, B, C\ldots$ on the left and a, b, c... on the right. We distinguish these from function operators, though the paper does not and relies on convention to distinguish between the two.

$A \dagger B \Leftrightarrow$ Bifunctor t => t a b
$A_F \Leftrightarrow$ Functor f => f a
$A* \Leftrightarrow$ [a]
$D \parallel D' \Leftrightarrow$ (d, d')
$D\ |\ D' \Leftrightarrow$ Either d d'
$_I \Leftrightarrow$ Identity
$\underline{D} \Leftrightarrow$ Const d
$A_{(FG)} \Leftrightarrow$ (Functor f, Functor g) => g (f a)
$A_{(F\dagger G)} \Leftrightarrow$ (Bifunctor t, Functor f, Functor g) => Lift t f g a
$\boldsymbol{1} \Leftrightarrow$ ()

Function operators. By convention, functions are $f, g, h\ldots$ on the left and f :: a -> b, g :: a' -> b', h... on the right (with types unified as appropriate).

$f \dagger g \Leftrightarrow$ bimap f g :: Bifunctor t => t a a' -> t b b'
$f_F \Leftrightarrow$ fmap f :: Functor f => f a -> f b
$f \parallel g \Leftrightarrow$ f *** g :: (a, a') -> (b, b')
where f *** g = \(x, x') -> (f x, g x')
$\grave{\pi} \Leftrightarrow$ fst :: (a, b) -> a
$\acute{\pi} \Leftrightarrow$ snd :: (a, b) -> b
$f \vartriangle g \Leftrightarrow$ f &&& g :: a -> (b, b')        -- a = a'
where f &&& g = \x -> (f x, g x)
$\Delta x \Leftrightarrow$ double :: a -> (a, a)
where double x = (x, x)
$f\ |\ g \Leftrightarrow$ asum f g :: Either a a' -> Either b b'
where asum f g (Left x)  = Left (f x)
asum f g (Right y) = Right (g y)
$\grave{\i} \Leftrightarrow$ Left :: a -> Either a b
$\acute{\i} \Leftrightarrow$ Right :: b -> Either a b
$f\ \triangledown\ g \Leftrightarrow$ either f g :: Either a a' -> b        -- b = b'
$\nabla x \Leftrightarrow$ extract x :: a
where extract (Left x) = x
extract (Right x) = x
$f \rightarrow g \Leftrightarrow$ (f --> g) h = g . h . f
(-->) :: (a' -> a) -> (b -> b') -> (a -> b) -> a' -> b'
$g \leftarrow f \Leftrightarrow$ (g <-- f) h = g . h . f
(<--) :: (b -> b') -> (a' -> a) -> (a -> b) -> a' -> b'
$(f \overset{F}{\leftarrow} g) \Leftrightarrow$ (g <-*- f) h = g . fmap h . f
(<-*-) :: Functor f => (f b -> b') -> (a' -> f a) -> (a -> b) -> a' -> b'
$f_I \Leftrightarrow$ id f :: a -> b
$f\underline{D} \Leftrightarrow$ const id f :: a -> a
$x_{(FG)} \Leftrightarrow$ (fmap . fmap) x
$VOID \Leftrightarrow$ const ()
$\mu f \Leftrightarrow$ fix f

Now, let's look at the abides law:

$(f \vartriangle g)\ \triangledown\ (h \vartriangle j) = (f\ \triangledown\ h) \vartriangle (g\ \triangledown\ j)$